Wpf showdialog multiple times. SelectedValue setter has called.

Wpf showdialog multiple times Exception when opening a Form using WPF's ShowDialog. I don't know what's the source of my problem! But I found out that the problem isn't from GetRegisterKey then I'll remove it's code from the question. NET Framework here). WpfDialogManagement. In answer to your comment about why it might behave the way it @Homero - This means that you are calling ShowDialog() after the window is closed (are you calling it multiple times on the same instance of the window?). ShowDialog(); } This works. Dispatcher. So, if you do not mark your event as handled in your event handler, it will bubble up the tree, and eventually arrive at your TabControl, which is causing this "firing too often" issue. This subtle I have a WPF Window created. It originates from Selector. ShowDialog returns DialogResult, so I really can't figure out how to do this. 5 and 4. Ask Question Asked 15 years, 4 months ago. ). You will probably will have to add some changes to XAML file (class name or etc). MainWindow property as expected without any intervention. cs works In a console-application starting a simple modal "Hello world" WPF dialog with "ShowDialog();" works fine. You have two options: Keep the same Window instance but change the Visibility to Hidden instead of closing it (as suggested in the answer above). My application has several independent "top-level" windows, which all have completely different functions/workflows. Mark your event as handled So if you are doing a Dispatcher. ShowDialog shows the window, disables all other windows in the application, and returns only when the window is closed. and keep showing them from the list of predefined folders . You don't need to return that value from the ShowDialog method, as explained here: "A Nullable<(Of <(T>)>) value of type Boolean that signifies how a window was closed by the user". ShowDialog(owner) and MessageBox. An information message and an error message. This result is reproducible -> trying 3 times is ok then the next try the password dialog is shown in background. Once your main window is constructed, it will be assigned to the App. ShowDialog() But you should never call Close() method (until you don't want to use the control anymore: Close is like Dispose for controls). 0/. If more processing is required, do another Dispatcher. StartNew here. Also, because it is such a bad design, what's stopping the VM from Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company WPF ShowDialog returns null immediately on second call . I readed if form is showing by ShowDialog then I should execute Dispose method, but why it works sometimes without it ? Edit: Collect method can be added after ShowDialog. I'm trying to //This is the folder that opens when the dialog is opened dialog. This worked find in winforms, but in WPF I recieve this exeception: System. Since TwoWay is the default Binding. – Fyodor Soikin. ? Can you post a minimal code sample that reproduces it for you? – This code snippet starts a worker thread, there's very little evidence that it actually creates the dialog on the worker thread as well. After looking at your code I understand that you are trying to animate the width and height of Window simultenousely. 1. As per the MSDN: When a Window class is instantiated, it is not visible by default. Try this and it will work. There are times **Mutex** is not working in some areas. I managed to print one window using PrintDialog and PrintVisual. 0. When you call ShowDialog on a WPF window twice like this: var window = new Window(); window. g. But after it closes, starting the same view again with ShowDialog does absolutely nothing: no view, no runtimeerror, no nothing - the programm just ignores it, There can be multiple GUI threads (and therefor multiple Dispatcher instances). You have to do an Alt-Tab to get to your newform. ShowDialog() fails to get window focus (pops under) when . In my example I want to display two different dialog type. Invoke() has completed. openFileDialog. (That a typical designer can't code for this logic, seems a secondary concern. XAML can swallow errors such as methods being mis-spelt, and then an exception is thrown on run time, this particularly true DataSet providers. See image. My problem is that, even when the text is empty, this dialog box opens and shows nothing. 5) (or returns Task rather than being void, for . I think this is a bug in the WPF framework, without going into depths of my program and why I am doing what I am doing, I wrote a simple test application to prove my theory. ItemCollection System. 0, A "blocking Window" is known in the UI world as a "modal dialog", and you show one by calling ShowDialog. ShowDialog() is called on a thread other than the UI thread for your main window. I am trying to keep one instance of a Window around and when needed call ShowDialog. I put a break point in The second time that MouseLeaveChanged fires (when the Dialog control is displayed) it displays the same, but just below the "External Code" it says Technewlogic. Gui. You'd be surprised what you can get away with. Windows. Make ShowDialog() after Show - WPF. ShowDialog() and it worked fine and the program didn't close. Have you looked at the WindowStartupLocation property for Window?. Update2. In WinForms there is similar functionality but it also has an overload Form. I want to create a document with several pages and with one wpf window depicted on each page. Here is my problem. ShutdownMode = ShutdownMode. A BackgroundWorker's thread is not suitable for UI, such a thread is not a single-threaded apartment and therefore does not permit common Windows facilities like drag+drop, the clipboard, cut and paste and shell dialogs. So I wanted to override this ShowDialog. This works like any other method call, so it causes the stack to grow. OnExplicitShutdown; var dialog = new Login(); I try to show the authentication window, then open the main window, but when you close the authorization window, application is stopped. Don't forget to call base. ShowDialog(); // returns when user closes first window window. Basically what's happening when you press your H key is that the Game loop executes, very, very quickly and the Update method The win32 task dialog will show one instance of itself, and other pending TaskDialogs to show will only show up after the first has returned (or actually it seems to block awaited task continuations) The problem is that my custom task dialog is showing multiple errors at the same time (from awaited tasks), showing up multiple times on the screen. You can only ShowAsync one ContentDialog at a time. You can think of ShowDialog as being I have another issue in converting my Winforms program to a WPF program. Modified 5 years, While both the Main and Countdown windows are shown the user can click a button to launch a 3rd I am working on a WPF application where multiple windows can be present at one time. I've found an answer here: WPF and ShowDialog() but it isn't suitable for me because I don't need an "always on top" tool window. Text to the view model the binding becomes TwoWay (source <--> target). By using the service method ShowDialog(Window dialogWindow) my MyApp. Viewed 23k times 24 . To check if method Dispose was executed I added breakpoint (in debug mode). Like using in console application. You can invoke the UI-Thread with the dispatcher: // call this instead of showing the dialog direct int the thread this. Sh ShowDialog in WPF throwing not agree with the current state. The TabControl. The Windows are shown using the Dispatcher and thus each Window has its own UI Thread, according to the WPF Thre While checking to see if the dialog is already open will work, I think this answer is more correct. Why don't you put an option saying upload more if they say yes show them dialog box again. VS debugger is always showing the crash coming from my 'form. WPF ShowDialog returns immediately. You really need to make sure that both, criteria are met: Your DoIt() Method has the async keyword (C# 5. NET, etc. Hot Network Questions How does exposure time and ISO affect hue? spray/paint effect - how to? Are Shell Script --long-options POSIX compatible? 80-90s sci-fi movie in which scientists did something to make the world @Luciferius the code for XmlTextWriter. NET Framework doesn't (see CoreFX here and . InputValue; Viewed 2k times 1 . await your long running task and the remainder of your method will run on the captured context. This goes on and on until the 11th touch happens. Everything works great until user walks away from the computer and there's modal dialog (other than the log-in In fact, had it completed before I called Run(), everything would have worked as I expected it to, because WPF application can be run several times in a row: start, stop, start again, stop again, and so on. I have a main window which when the application is loading data from the data source, opens another small window as a dialog to show the WPF public class OptionsDialog : Window { public OptionsDialog(MyAppOptions options) { chkBooleanOption. Hot Network Questions Acro package not working in figure captions This view-related logic belongs in the view itself. But I don't see it in the code you provided, so the problem is probably with something else. I think what you are referring to is the subtle difference in PartBasedPackageProperties. ItemContainerGenerator System. I've watched some Brian's videos to learn about this two arguments. In MainWindow class You should only open the Dialog from the UI thread. Hot Network Questions Pete's Pike 7x7 puzzles - Part 3 @MarkA. However, in my OK and Cancel button's click events in the dialog window I set this. Loaded += WindowALoaded(); WindowALoaded { window b. ShowDialog(); new MainWindow(). The related Edit: WPF Command bindings are async/Task aware. SelectionChanged. I have some cases where i want to display it using ShowDialog() and others just using Show(). Controls. ShowDialog(); } After searching, here is the answer: add WindowAbout = New FormAbout 'Window Main Class MainWindow Dim WindowAbout As FormAbout = New FormAbout Private Sub Button_Click(sender As Object, e As RoutedEventArgs) WindowAbout = New FormAbout WindowAbout. On response to the Loaded event an action is executed and the window is closed so the application continues its work. Then, after the "await ShowAsync" of the second ContentDailog, your simply call "var T = this. String, mscorlib, Version=4. However a couple of people have reported that when they press the browse button nothing happens. Hot Network Questions Is sudoku only one puzzle? Viewed 1k times 4 . any such changes are routed through Pinvoke. Data. NET Framework. The trick to do this, is using two data templates, which define the appearance of each dialog. 0. showdialog. Run the TestApp, show the newform. But after it closes, starting the same view again with ShowDialog We currently have this implemented in WPF by simply calling WPF ShowDialog, which is already sync, on STA Thread, which is not the Console Application main thread. Viewed 12k times 3 . These days, I don't do much of WinForms/WPF development, but I was to touch this code, I'd probably change it to throw an exception if IsDisposed is true. This happens because unlike the Show() method, ShowDialog() doesn't return until the window that it displays is closed. I have some cycle in MainMethod. ShowDialog() didnt show dialog. I have a window that I sometimes open using Show() and sometimes using ShowDialog(). But first lets start with In C# WPF (Windows Presentation Foundation) applications, the ShowDialog method plays a crucial role in displaying dialog windows. I'm new on WPF develpment with Prism Framework. You can simply store the value you want to return in a property or field and get it: window. Invoke() my . with DotNetCore 3 Preview 3: In a console-application starting a simple modal "Hello world" WPF dialog with "ShowDialog();" works fine. InvalidOperationException: Cannot set Visibility or call Show, ShowDialog, or WindowInteropHelper. however content of window is completely controllable as expected via your code, but window is not. MainWindow to the first window opened. EnsureHandle after a Window has closed" problem. The window opens and is modal as expected. Close(), the ShowDialog() won't return until after the Dispatcher. Click += new RoutedEventHandler(btnOK_Click); btnCancel. When you do that the Show function returns immediately and the form stays open. ShowDialog(), click "show Desktop" on your taskbar or Quick launch toolbar, click on the TestApp on the taskbar. –. Close WPF window after animation. Thanks WPF's Window. ) So that's how I have done it. Show(); // Then application stopped } I often call MessageBox or ShowDialog on a window in the main window's WindowClosing event handler in WPF. C# NullReferenceException was unhandled. I guess I don't see where this is unexpected behaviour. There can be multiple file in same folder option. dll now has a direct dependency on WPF assemblies (namely to resolve Window). So I tried using WMI Query. MainWindow = Null there. After that it is done for. This shows the form modeless. Is this a bug in Viewed 321 times 0 . ShowDialog() which allows showing a modal dialog box. Here is cycle private void WPF Modal Window using ShowDialog() Blocks All Other Windows. Invoke((Action)delegate() { // Here you can show your dialiog }); I can execute this code as many times as I want until the exception is thrown which is when the message above is displayed on show dialog. But if I set the DialogResult after calling Show() I get an InvalidOperationException. ShowDialog() End Sub End Class ----- 'Window About Imports After each process(on other forms), I create this form and call ofrmDialog. clear text boxes, etc. Commenting out the indicated line in MainWindow. IsChecked = options. WPF ShowDialog again/several times. In the second case, the returned dialog result is important for me. This method is only for tests and is executed multiple times. That's a strange and potentially annoying (for the users) application requirement that you are asking about here. The window. SingleBorderWindow; to open a modal window in my WPF (MVVM) application, but it lets me navigate to parent window using the Windows taskbar (Windows 7). SelectionChanged is the same event as a ComboBox. Failing to display a custom WPF dialog box more than This is what you need to do in case you didn't do it already : Remove the StartupUri from the Application XAML file. 2. I haven't had this problem. ShowAync()" to unhide it. I'm trying to open multiple files at once with the OpenFileDialog, using FileNames instead of FileName. (printDlg. However: Simply creating a new window (modal or not) does not create a new GUI thread. ShowDialog shows the form modally. WPF sets App. Invoke() to get the ShowDialog() to return. But I cannot see any examples anywhere on how to accomplish this, not even on MSDN. You can define a new class based on Window with overriden/new ShowDialog() method, which sets public property bool IsModal to true if it is called. WPF OpenFileDialog Suppresses Exception. ; Create a new instance of the Window General. SomeBooleanOption; txtStringOption. Is there a way to find out which method was used to open the window and set or not the DialogResult accordingly? Or is In WPF application, I would like to show window b as a dialog inside window a when window a is loaded. Flush() which in CoreFX always closes the underlying stream and in . If your ICommand. When I show it the second time, I am getting "Cannot set Visibility or call Show, ShowDialog, or WindowInteropHelper. ShowDialog calls are slow. Hot Network Questions I found that window. This means that the form will show, all other forms will be disabled, and the ShowDialog function will not return until the modal dialog is closed. update. ShowDialog()' instead of the code thats actually creating the crash. Code. ShowDialog. Mode for the TextBox. ShowDialog() seems to hang from time to time (very rarely) without showing the dialog and the Loaded event is not fired so the application hangs. You might need to reset the Window in between uses (e. WPF ShowDialog returns null immediately on second call . Perhaps it is important, that SelectedValue is bindable property of MyUserControl class with It is shown on the main thread using a window. I am creating a wpf form which is going to be used for adding/editing data from datagrid. MTObservableCollection`1[[System. I am currently using ShowDialog() to make a WPF Window modal. ShowDialog(). However when I check for ShowDialog() == true I am getting the above exception. ShowDialog(this), click "show Viewed 2k times 2 I have a WPF application which mostly works just fine. Owner = this; w. Since you are calling ShowDialog() multiple times without closing, each call increases the stack depth, and the stack eventually overflows. What version of windows, . It is much more common to display different views in one Window, rather than displaying different Windows, but you're still entitled to do that. I added my own ShowDialog() method to Per this answer (and my experience), WPF Windows cannot be shown again once closed. Window. The code is taken from a book (Windows Presentation Foundation 4. Only Alt+Tab brings the dialog to foreground. I'm having a problem with the code behind the WPF when it crashes. I have a main window which has some menu buttons leading off onto other WPF windows. When I call the function for the first time - everything is Ok, window is showing and function waits for it to close. This statement is not entirely true. Viewed 335 times 0 . If you designate this as the Cancel button and call . The advantage of this solution is: The ShowDialog(owner) will wait until the user closed the dialog, but the other forms of your app are still usable furthermore, and it's very easy to implement for all of your ShowDialog(owner Same thing happens when the third touch occurs, WPF creates touchHandler3. Invoke() I am using ShowDialog() with WindowStyle = WindowStyle. private void ApplicationStartup(object sender, StartupEventArgs e) { Current. private async void Window_Loaded(object sender, RoutedEventArgs e) { Storyboard board = AFAIK, a modal dialog (which . Basically all is working fine, but if I want to change in the protected tabitem more than 3 times with entering a wrong password the modal password view did not show in foreground. Viewed 2k times 0 . I'm assuming your code came from Window_Loaded or similar event handler:. ShowDialog(); //Show the file selection dialog Viewed 4k times 7 . WPF only supports 10 multi-touches (because human beings have 10 fingers), now it treat this 11th touch as part of the tunneling and bubbling sequence of touchHandler1, and completes touchHandler1. Current. private void App_OnStartup(object sender, StartupEventArgs e) { new LoginWindow(). ShowDialog(ownern) and FileOpenDialog. EnsureHandle after a Window has closed. For me the problem went away when I made sure to . Execute returns Task or Task<T>, then WPF will run them asynchronously. SomeStringOption; btnOK. ShowDialog(); // Retrieve results / propagate exceptions var results = await task; One annoyance I found with ShowDialog() vs ShowDialog(this). ShowDialog() triggers) blocks all other windows thereby Activation events. WPF ShowDialog doesn't display dialog. So does CommonDialog. WPF ShowDialog with another Window Active. I used form2. ViewModels. And then I know that the pause contains two part. For saving your time and better understanding of my issue,i will write short. // Start the long-running operation var task = LongRunningOperationAsync(); // Show the dialog progressWindow. Now, I understand cases where these would return false (user clicked Cancel or pressed Esc), and when they The method always returns true or false, and this is always equal to the DialogResult property of the window at the time it closes. In WPF we have Window. 1 "Only a single ContentDialog can be open at a time". ShowDialog(); to I show a WPF window using ShowDialog() from the calling window. If you do this, the new Window will run in a separate thread, so any heavy processing or blocking of threads beyond that Clicking the button multiple times keeps increasing the number of dialogs open (ShowDialog () calls). var folderpath = new List<string>() { "c:", "d:" }; @Servy, I think the point here is to create a dialogue that will display a progress bar and perform an arbitrary task on a secondary thread. Every time it appears before MyUserControl. xaml. WPF: Open and Close windows. Set startup handler in app XAML : Add the Show() to MainWindow after the dialog show : . ShowDialog(IWin32Window) which allows an IWin32Window owner to be passed in. I tried to create a new instance of GetRegisterKey in Windows_loaded event of MainWindows and I called grk. Viewed 90k times 39 . So the simple solution is to return from the Dispatcher. NET 4. In my first program, I had a smaller window open to allow the user to adjust some data, and then when it closed, the other form was activated again with the new data. You've added your own call to Close() and canceled the close, so both calls are made and the event is raised both times. 3 Performance problems with displaying a WinForm dialog from WPF application. By having a BackgroundWorker in the dialogue but the methods that handle the events somewhere else, you can write your task-related code in, for instance, a main form and have it executed asynchronously and overlaid with a I am working on a WPF desktop application, which has screen-lock feature that shows the log-in dialog after application is inactive for some time. VS. Update. Close() disposes the text writer both in CoreFX and . However, it is blocking all the top-level windows once it is open. Donohoe, I think your suggestions make sense, I didn't test all code paths for this snippet at that time. In this post, we will delve into how This would let Model-View-ViewModel (MVVM) programs show dialogs without touching the XAML's code behind; a feat not currently possible with Windows Presentation Inside a custom dialog box, you can implement modal behavior yourself to restrict the user to only interact with that dialog box. It takes around 5~10s to show the window. Modified 10 years, 8 months ago. . You can call several times Window. ShowDialog Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; I sent OtherForm as parameter from MainWindow to usercontrol. 5. In my case, the users have 2 monitors. 538. . -1 for the second, poorly-advised paragraph. I offer it only as a suggestion, there is probably other ways of thinking about it, and I hope you get more replies too. Text = options. WPF ShowDialog swallowing exceptions during window load. 0) You use await for EVERY long A WPF window dialog is shown using the ShowDialog method in the Window class like when a button is pressed on the main window, like this. Event handlers' code has been profiled with my own profiler based on StopWatch. It shows the Mainform. SelectedValue setter has called. ShowDialog method without blocking other windows in WPF. ShowDialog() <> True) Then Return Dim formattedText As It still worked kinda, sorta most of the time, but many times the modal window would be stuck behind, just as you described, especially when switching between multiple application windows. If you have control over the secondary window constructor, just set App. ShowDialog in WPF. Click += new RoutedEventHandler(btnCancel_Click); } public MyAppOptions Animation occurs only first time in wpf. CenterScreen places the Window in the center of the screen containing the cursor, which should normally be fine. If you call ShowDialog again you get this exception:. But when I call this function for the second time - window doesnt displayed and I immediately goes to the next line. is it possible to display a Modal Window from a WPF User Control, that is a child of an ElementHost, and set the owner/parent of the Modal Window to the containing Form control? WPF ShowDialog() doesn't return if owner window is programatically closed. Cannot set Visibility or call Show, ShowDialog, or WindowInteropHelper. dll!Technewlogic. I really encourage you to take several steps back, think twice and try to approach the problem from some different side before actually doing what you asked. Hot Network Questions Luke 20:38 | "God" or "a god" One or more of the following sources may have raised the wrong events: System. ShowDialog() on the correct UI thread. You basically need a parent class, maybe MainWindow. And in usercontrol I am calling OtherForm. Invoke() onto your thread to call MainWindow. Seems kind of lame to me, but those are the rules. In the parent form or control, when you need to WPF Window can be used in another thread if it is a Single Thread Apartment, so ShowDialog is okay. I'm working on a complex WPF application, and sometimes the simple Window. Is there any possibility to make an already shown Window in to a Model Dialog (Like what happens when we call ShowDialog()) Blocking or Non Blocking, Any solution is acceptable for me, but all the Windows in the background should be disabled. Because you also want to send input data from the TextBox. ShowDialog(); Tuple<string, string> value = window. But you should check first if you need to add IsModal property on your class instance. DialogResult = true (or false) respectively, and the value does not get set. ShowDialog in WPF throwing not agree with the current state. ShowDialog(); // throws you will get an InvalidOperationException with this message: Cannot set Visibility or call Show or ShowDialog after window has closed. ListCollectionView * XmlDiff. However, it displays window b, and window a does not get displayed until I close window b. I do this with the following pseudocode: window a. The view model assembly has tight coupling to presentation types. Several issues: 1) Since you want to send the Helper (view model default) values to the TextBox. For the ShowDialog() i want to set the DialogResult which all works fine, however if the window is launched using Show() and i set the DialogResult i get the exception There's no need to use Task. DialogLayeringHelper. All you need to do is hide the current ContentDialog before opening another one. EnsureHandle after a Window has closed Update. 4. The code is executing on the main UI thread. ShowDialog failes on return. We all need help some times. But I would regret to tell you that since window is not an actual wpf component but a platform component. Text the binding must be at least OneWay (source --> target). 5 Cookbook). ShowDialog(), then clicking the button will close the window. cs?This class can hold references to the three Windows and be in Here is a working solution for Form. Text property you First of all, whatever your goal is in the end, it can probably be reached in a different way. I don't think any picker gives multiple folder by default. Show(text). /// <summary> /// The main entry point for the application. I am developing an app with WPF. wpf fade in animation working just one time. Factory. The window closes as expected, but DialogResult is still null. Viewed 6k times 17 . I have a little problem when opening a window by ShowDialog. That way the new dialog is not modal, and always maintains a z-order directly above its owner. Ask Question Asked 5 years, 10 months ago. ShowDialog method returns a nullable boolean. The modal window is a child of one of the main windows. For example, if a user clicks a button on your Window and a dialog opens, the cursor will still be over the button and thus the dialog will show up in the center of the same i am new to WPF, and i am trying to open a modal dialog from inside my main window: public partial class MainWindow : Window { protected void OpenCommandExecuted(object target, ExecutedRoutedEventArgs e) { DataSearchWindow w = new DataSearchWindow(); w. In my WPF application I use this code to open a new windows from a button: private void LoginBtn_Click(object sender, RoutedEventArgs e) { LoginDialog dialog = new LoginDialog(); dialog. Use Show instead. NET 3. What's the difference between In WPF you get to call ShowDialog on a window exactly once. fqmwth cpau yyjtu tigs oceldn aicbptn qhve oksulyl grpaq gxsex